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Why Evolutiontheory is just a theory and not an Evidence

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  • so each question Al Hanif has got wrong

    Afghanistan got his chemistry question wrong and even confused Isotope with Isomer hahahaha


    these guys are both fakes and uneducated losers

    Comment


    • Originally posted by ScimitarXEdge View Post
      your case would not apply because there is no general formula.
      I never said there was a general formula. I said that
      Originally posted by Al Hanif View Post
      an Irrational raised to an Irrational can be Rational ?
      Originally posted by ScimitarXEdge View Post
      by definition of open set E (epsilon) is a neighborhood
      A number is a neighborhood ?


      Originally posted by ScimitarXEdge View Post
      in an Open set Xi, around x which is an element of Xi, if x exists in Xi,
      You prove that something exists after using it ?


      Originally posted by ScimitarXEdge View Post
      then the neighborhood of x
      No verb ?


      Originally posted by ScimitarXEdge View Post
      epsilon exists i Xi
      i ?


      Originally posted by ScimitarXEdge View Post
      and thus the Union Xi, i=1--> Infinity contains Epilson and therefore the Infinite Union of an Open set is open.
      An union of sets contains a number ?


      LOL

      Comment


      • Originally posted by ScimitarXEdge View Post
        remember I asked prove there an Irrational raised to an irrational is rational, NOT ALL irrationals raised to a irrational
        NO. What you asked was :

        Originally posted by ScimitarXEdge View Post
        prove that the an Irrational raise to an irrational is rational :p
        Learn to speak english. You don't even ask your questions correctly.

        Comment


        • Originally posted by Al Hanif View Post
          I never said there was a general formula. I said that

          You have an N^N, which is wrong, because you have to restrict N, you gave a general N.




          A number is a neighborhood ?
          A Neighborhood is a distance, sometimes range surrounding a number which contains values within that range, if those range of value exist in the set, then the set is open. You could have used Epsilon Ball, I'd have accepted that but your explanation was non-explicit

          which means you did not learn this stuff except 10 minutes ago by web searching. Precision is important in Mathematics.



          You prove that something exists after using it ?

          It's the basis of the proof , you have to use definition of open set.


          No verb ?




          i ?




          An union of sets contains a number ?
          Union of sets contains epsilon, you can almost think of it as subset

          Comment


          • Originally posted by Al Hanif View Post
            NO. What you asked was :



            Learn to speak english. You don't even ask your questions correctly.
            yes "an" is just ONE ...not all, you should learn English in the first place

            Comment


            • Originally posted by ScimitarXEdge View Post
              You have an N^N, which is wrong, because you have to restrict N, you gave a general N.
              No, I said that N was a square root of a non-squared number. N is not general.


              Originally posted by ScimitarXEdge View Post
              A Neighborhood is a distance, sometimes range surrounding a number which contains values within that range, if those range of value exist in the set, then the set is open. You could have used Epsilon Ball, I'd have accepted that but your explanation was non-explicit
              Bull****. I don't know what you're talking about. Neighborhoods are not numbers but mathematical objects in a topolgical space. The neighborhood of a point is a set, not a number.


              Originally posted by ScimitarXEdge View Post
              It's the basis of the proof , you have to use definition of open set.
              That's completely false. Your proof is false.


              Originally posted by ScimitarXEdge View Post
              Union of sets contains epsilon, you can almost think of it as subset
              An union of sets contain a number ?

              You can't even spell correctly. Learn to speak english

              Comment


              • Originally posted by Al Hanif View Post
                No, I said that N was a square root of a non-squared number. N is not general.
                Which is still wrong, because you can't use any general square root of a non squared number and get the same result, for example Sqrt (3).

                Your definition was too general; hence wrong!!!!

                Bull****. I don't know what you're talking about. Neighborhoods are not numbers but mathematical objects in a topolgical space. The neighborhood of a point is a set, not a number.
                yeah dumb dumb I never said it's a number, I said it's a distance, a range which is a set., it's a subset

                remember my remark
                Originally posted by read my quote again
                A Neighborhood is a distance, sometimes range surrounding a number which contains values within that range, if those range of value exist in the set, then the set is open. You could have used Epsilon Ball, I'd have accepted that but your explanation was non-explicit

                That's completely false. Your proof is false.
                Prove why it's wrong then, I proved why yours is wrong


                An union of sets contain a number ?

                You can't even spell correctly. Learn to speak english
                The Union of sets contains an ELEMENT< it doesn't have to be a number, were not doing Real Analysis here, it can be, and that element is contained within an Epsilon, which itself is contained within the set, which proves the Union of sets is open.

                Stop making a fool of yourself

                you're not a mathematician, Mister "It's Just a Theory" hahahaha

                Comment


                • Originally posted by ScimitarXEdge View Post
                  yeah dumb dumb I never said it's a number, I said it's a distance, a range which is a set., it's a subset
                  a distance is not a set hahaha


                  Originally posted by ScimitarXEdge View Post
                  Prove why it's wrong then, I proved why yours is wrong
                  I already did. Your demonstration is false because you don't even understand the difference between a number, a distance and a set.


                  Also you can't even speak english correctly, no wonder why I didn't understand your question.

                  Comment


                  • Originally posted by Al Hanif View Post
                    a distance is not a set hahaha
                    Native English speaker here -- a range is most definitely a set, it is just not portrayed in standard notation. There is nothing mathematically incorrect stating the set {1,2,3,4,5} and saying the set of natural numbers between 1 and 5, inclusive, which is a range. It's not the preferred notation, but it is common to refer to sets as ranges. Every math professor I have ever had has used this short hand at some time.



                    I already did. Your demonstration is false because you don't even understand the difference between a number, a distance and a set.
                    Evidently you have translation errors, and need to take a deep breath and come at this issue a little less antagonistically.



                    Also you can't even speak english correctly, no wonder why I didn't understand your question.
                    You seem to have similar issues.
                    Last edited by ozymandias; 10-11-2011, 02:28 PM. Reason: fix broken tags
                    -------------------------------------------------

                    "There was so much to grok, so little to grok from. "

                    "Ph'nglui mglw'nafh C'thulhu R'lyeh wgah'nagl fhtagn"

                    أنا آسف ، أنا لا أقرأ أو لا يتكلم اللغة العربية. وسوف تبذل جهدا لترجمة مع ترجمة جوجل. يرجى أن يكون فهم من هذا الحاجز.
                    (I'm sorry, I do not read or speak Arabic. I will make an effort to translate with Google translate. Please be understanding of this barrier.)

                    Comment


                    • Originally posted by Al Hanif View Post
                      [B]a distance is not a set hahaha
                      a distance can definitely be a set ...for example a distance between A and B can contain a number C, D, and E, which makes it set. Distance can be described of as a range.

                      I already did. Your demonstration is false because you don't even understand the difference between a number, a distance and a set.
                      Nah you just cried and shunned it; this isn't a proof or disproof of anthing. LOL



                      Also you can't even speak english correctly, no wonder why I didn't understand your question.
                      Even other English speakers like Ozymandias understood me fine.
                      Last edited by ScimitarXEdge; 10-11-2011, 02:34 PM.

                      Comment


                      • Originally posted by ScimitarXEdge View Post
                        a distance can definitely be a set ...for example a distance between A and B can contain a number C, D, and E, which makes it set. Distance can be described of as a range.



                        Nah you just cried and shunned it; this isn't a proof or disproof of anthing. LOL



                        Even other English speakers like Ozymandias understood me fine.
                        To be fair, a native speaker is likely to have an advantage understanding you over a non-native speaker.
                        -------------------------------------------------

                        "There was so much to grok, so little to grok from. "

                        "Ph'nglui mglw'nafh C'thulhu R'lyeh wgah'nagl fhtagn"

                        أنا آسف ، أنا لا أقرأ أو لا يتكلم اللغة العربية. وسوف تبذل جهدا لترجمة مع ترجمة جوجل. يرجى أن يكون فهم من هذا الحاجز.
                        (I'm sorry, I do not read or speak Arabic. I will make an effort to translate with Google translate. Please be understanding of this barrier.)

                        Comment


                        • Originally posted by ozymandias View Post

                          You seem to have similar issues.
                          exactly

                          look at this dimwit ...case and point


                          Originally posted by Al Hanif View Post


                          MOAR QUESTIONS !!!
                          he can't even spell a basic word like MORE

                          Comment


                          • Originally posted by ozymandias View Post
                            Native English speaker here -- a range is most definitely a set, it is just not portrayed in standard notation.
                            He added the word range after he made his mistake. A distance is definitely not a set.


                            A metric on a set X is a function (called the distance function or simply distance)
                            d : X × X → R
                            (where R is the set of real numbers). For all x, y, z in X, this function is required to satisfy the following conditions:
                            d(x, y) ≥ 0 (non-negativity)
                            d(x, y) = 0 if and only if x = y (identity of indiscernibles. Note that condition 1 and 2 together produce positive definiteness)
                            d(x, y) = d(y, x) (symmetry)
                            d(x, z) ≤ d(x, y) + d(y, z) (subadditivity / triangle inequality).


                            Originally posted by ozymandias View Post
                            Evidently you have translation errors, and need to take a deep breath and come at this issue a little less antagonistically.
                            Yeah, yeah don't take me as if I was a fool. He said that a distance is a set which it is not, even in English. And he couldn't even spell correctly his question twice.

                            Originally posted by ScimitarXEdge View Post
                            prove that the an Irrational raise to an irrational is rational :p
                            Originally posted by ScimitarXEdge View Post
                            remember I asked prove there an Irrational raised to an irrational is rational, NOT ALL irrationals raised to a irrational
                            Learn to speak english, learn what is a set and what is a distance and then talk to me.

                            Comment


                            • Originally posted by ScimitarXEdge View Post
                              exactly

                              look at this dimwit ...case and point




                              he can't even spell a basic word like MORE

                              Actually, "MOAR" is a meme -- an internet joke.
                              -------------------------------------------------

                              "There was so much to grok, so little to grok from. "

                              "Ph'nglui mglw'nafh C'thulhu R'lyeh wgah'nagl fhtagn"

                              أنا آسف ، أنا لا أقرأ أو لا يتكلم اللغة العربية. وسوف تبذل جهدا لترجمة مع ترجمة جوجل. يرجى أن يكون فهم من هذا الحاجز.
                              (I'm sorry, I do not read or speak Arabic. I will make an effort to translate with Google translate. Please be understanding of this barrier.)

                              Comment


                              • Originally posted by Al Hanif View Post
                                He added the word range after he made his mistake. A distance is definitely not a set.
                                How can this be? You *QUOTED* the word 'range'. Even if he added it later, you should reply to what you quoted, not what he may have had prior to editing.


                                A metric on a set X is a function (called the distance function or simply distance)
                                d : X × X → R
                                (where R is the set of real numbers). For all x, y, z in X, this function is required to satisfy the following conditions:
                                d(x, y) ≥ 0 (non-negativity)
                                d(x, y) = 0 if and only if x = y (identity of indiscernibles. Note that condition 1 and 2 together produce positive definiteness)
                                d(x, y) = d(y, x) (symmetry)
                                d(x, z) ≤ d(x, y) + d(y, z) (subadditivity / triangle inequality).




                                Yeah, yeah don't take me as if I was a fool. He said that a distance is a set which it is not, even in English. And he couldn't even spell correctly his question twice.
                                Once again, you quoted him saying 'range'.





                                Learn to speak english, learn what is a set and what is a distance and then talk to me.
                                Learn to capitalize 'English', spell correctly, and use proper grammar, and then talk about others needing to learn English.


                                You guys really need to grow up, drop the personal attacks and act like adults. I am starting to feel embarrassed for the both of you, bickering like little kids.
                                -------------------------------------------------

                                "There was so much to grok, so little to grok from. "

                                "Ph'nglui mglw'nafh C'thulhu R'lyeh wgah'nagl fhtagn"

                                أنا آسف ، أنا لا أقرأ أو لا يتكلم اللغة العربية. وسوف تبذل جهدا لترجمة مع ترجمة جوجل. يرجى أن يكون فهم من هذا الحاجز.
                                (I'm sorry, I do not read or speak Arabic. I will make an effort to translate with Google translate. Please be understanding of this barrier.)

                                Comment

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