Random Thoughts(New)

[sahil112]

LOL! oooooh DUH! >.<
i need to go over my oldd math notes hahaha


yeah i get all that so you get the 2 intersections.. i just didn't know what to do for the first step LOL :P mananaaaa

ur welcomee and yh i gt confused i was mixing it up with my A2 maths and ****

p.s as maths is first year cal for us and den A2 is the mre advanced

[sahil112]

ok gve me another :D uv gt me started nw ima use u for revsion LOLL sorry

[Qandahrii_Queen]

dere sandarey awre... da sandaro nya ye...

Woke i no,, da sandaro NYA ye??? Mana tchishi???

[Gulalai]

ur welcomee and yh i gt confused i was mixing it up with my A2 maths and ****

p.s as maths is first year cal for us and den A2 is the mre advanced

lol you mean calc? & lol yeah, this is just review stuff so he wont teach it to us again >.<

ok gve me another :D uv gt me started nw ima use u for revsion LOLL sorry

LOL ok but you sure you can take the square root like that? thought you couldnt because of the + between the parenthesis but then again what do i know hahaha ok lets seeeee hmmmmm...

ok heres a good one.

A circle (equation of the circle: x^2 + y^2 = 25) intersects a line (equation of line: 3x+y=15) at 2 points.
-find the points of intersection
-find the midpoint of the line between those two points of intersection.
-find the equation of the line passing through the origin and this midpoint.


and i've done this so i have the answers to this one lol

[Qandahrii_Queen]

GudnitOs pf!

[Gulalai]

^ shpa de pa khair (:

[emkhan]

good night

[Haris]

Shpa pa khair everyone.

[sahil112]

lol you mean calc? & lol yeah, this is just review stuff so he wont teach it to us again >.<



LOL ok but you sure you can take the square root like that? thought you couldnt because of the + between the parenthesis but then again what do i know hahaha ok lets seeeee hmmmmm...

ok heres a good one.

A circle (equation of the circle: x^2 + y^2 = 25) intersects a line (equation of line: 3x+y=15) at 2 points.
-find the points of intersection
-find the midpoint of the line between those two points of intersection.
-find the equation of the line passing through the origin and this midpoint.


and i've done this so i have the answers to this one lol

ok get ready for long answer aha :D

x^2+y^2=25 and 3x+y=15 this becomes: y=15-3x and then sub this into the first equation to get: x^2+(15-3x)^2=25 and then expand etc to get 10x^2-90x+225=25 which then becomes: 10x^2-90x-200=0 and then divide by then to get: x^2-9x-20+0

bracket this to get: (x-5)(x-4) so your x values are: 5 and 4. sub this back into 2nd equation we wer given to get y equales to 0 and 3 so the 2 points are: (5,0) and 4,3)
thats thew first part dun

part 2: we use our rule of (x(1)+x(2))/2, (y(1)+y(2))/2 which is basicaly (5+4)/2, (0+3)/2 and you get: (9/2, 3/2) and we have gt ur midpoint

last bit : use this to get gradient: y(2)-y(1)/x(2)-x(1) which is: (3/2-0)/9/2-0) which basicaly becomes 1/3

nopw use your formula: y-y(1)=m(x-x(1)) which is: y-3/2=1/3(x-9/2) get rid of the 2 on y side so u get: 2y-3=2/3(x-9/2) and then times out to get: 2y-3=2/3x-3 and then it becomes: 2y=2/3x and you can leave it like this or make it simpler: and divide by the 2 to just leave y on its own and u get: y=1/3x

[sahil112]

and gd nyt 2 da ppl goin lol

[Gulalai]

^ shpa de pa khair Haris, and Emkhan

ok sahil, i followed what you did on the other problem.... LOL these answers make no sense at all, so i give up :D
i'll let you know when i find the correct answer :P

lol i'll read your long response now >.<

[sahil112]

^ shpa de pa khair Haris, and Emkhan

ok sahil, i followed what you did on the other problem.... LOL these answers make no sense at all, so i give up :D
i'll let you know when i find the correct answer :P

lol i'll read your long response now >.<

lol u wnt alwys get excat points:P so yh chek and let me nw etc and yh read dat and yh

[Gulalai]

ok get ready for long answer aha :D

x^2+y^2=25 and 3x+y=15 this becomes: y=15-3x and then sub this into the first equation to get: x^2+(15-3x)^2=25 and then expand etc to get 10x^2-90x+225=25 which then becomes: 10x^2-90x-200=0 and then divide by then to get: x^2-9x-20+0

bracket this to get: (x-5)(x-4) so your x values are: 5 and 4. sub this back into 2nd equation we wer given to get y equales to 0 and 3 so the 2 points are: (5,0) and 4,3)
thats thew first part dun

part 2: we use our rule of (x(1)+x(2))/2, (y(1)+y(2))/2 which is basicaly (5+4)/2, (0+3)/2 and you get: (9/2, 3/2) and we have gt ur midpoint

last bit : use this to get gradient: y(2)-y(1)/x(2)-x(1) which is: (3/2-0)/9/2-0) which basicaly becomes 1/3

nopw use your formula: y-y(1)=m(x-x(1)) which is: y-3/2=1/3(x-9/2) get rid of the 2 on y side so u get: 2y-3=2/3(x-9/2) and then times out to get: 2y-3=2/3x-3 and then it becomes: 2y=2/3x and you can leave it like this or make it simpler: and divide by the 2 to just leave y on its own and u get: y=1/3x

lol yeah that's all basically what i did except i took some short cuts like instead of subing for 1) i just set them equal to each other, and i already knew one of the points just by graphing so made it easier to know where to go. & in the last part we already know that the line is passing through the origin so we know b=0 for the equation y=mx+b so idk why you went through the whole thing after finding the slope you could have just plugged it into the equation of a line and said y = 1/3x :D

and lol it's hard reading math from text like this :S LOL y(1) i would have written it as ysub1 :D

lol u wnt alwys get excat points:P so yh chek and let me nw etc and yh read dat and yh

well yeah but they seem way off. ok inshallah i will let you know tomorrow when i come back to the problem :P
and yeah >.<

[sahil112]

lol yeah that's all basically what i did except i took some short cuts like instead of subing for 1) i just set them equal to each other, and i already knew one of the points just by graphing so made it easier to know where to go. & in the last part we already know that the line is passing through the origin so we know b=0 for the equation y=mx+b so idk why you went through the whole thing after finding the slope you could have just plugged it into the equation of a line and said y = 1/3x :D

and lol it's hard reading math from text like this :S LOL y(1) i would have written it as ysub1 :D

its just the way iv been thought init so its just stuck in my head ahah and i do need to brush up on my a level maths skills anyway so il get to a bit of past papers soon and get myself upto date! havnt dun maths in a year aha!!!!

[Talal]