Random Thoughts part 2 :D

[Char$i]

This place seems to be dead :S

[Haris]

[sahil112]

whats da function^^^

(a+b)(a^2-ab+b)

[sahil112]

another method wud be if uv gt it in this form:

ax^3+bx^2+cx+d

u cud do dis:

(ax^3+bx^2)+(cx+d)

and factor thru like that

[sahil112]

u get (x-6)(2x^2-3x-7)

[Gulalai]

lol but how did you get that? :P

(2x^3 - 15x^2)(11x + 42) ? then what?

[sahil112]

i said derz 2 wayz gul :P i used first method :P

basicaly im nt gna fully help u ahah but il start u of, u alwys need to get the x term out into the first bracket and then the first term in ur 2nd bracket has to gve the first coffiencet when timesd together wid the x from first bracket

like this:

(x+-b)(ax^2-cx+d)

so in our case we wud have:

(x...)(2x^2... ...)

nw u mve onto the 2nd coffiencnt in the original given term which was -15x^2 hw we gna get dis what do we have to tyms x by?

(x...)(2x^2-3x...) should give you the power of 2nd coffiencent and then what 2 numbers timesd 2geda gve u 42? 6 and 7 right nw sub those in using plus and minus till u get the correct answer or if u can see easily ul no its just both minus


sorry its really hard to explain on here its easily dun face 2 face aha!

[Gulalai]

i said derz 2 wayz gul :P i used first method :P

basicaly im nt gna fully help u ahah but il start u of, u alwys need to get the x term out into the first bracket and then the first term in ur 2nd bracket has to gve the first coffiencet when timesd together wid the x from first bracket

like this:

(x+-b)(ax^2-cx+d)

so in our case we wud have:

(x...)(2x^2... ...)

nw u mve onto the 2nd coffiencnt in the original given term which was -15x^2 hw we gna get dis what do we have to tyms x by?

(x...)(2x^2-3x...) should give you the power of 2nd coffiencent and then what 2 numbers timesd 2geda gve u 42? 6 and 7 right nw sub those in using plus and minus till u get the correct answer or if u can see easily ul no its just both minus


sorry its really hard to explain on here its easily dun face 2 face aha!

[Breshna]

Ní féidir...le roinnt...daoine a chur ar an...fhírinne .


Ach siad ... díospóireacht.

Cad iad ... do.

[Laila]

I should really be working on my paper but i am too busy doing nothing!!!

[Laila]

lailo check your messages LOL

I just did and i dont see anything :\

[Laila]

not here :P

wait, there is nothing there either

[Iqra]

Wheres Admiiin khan??

[Haris]

hahaha

[Haris]

^